Advertisements
Advertisements
प्रश्न
Factorise : (a2 − b2) c + (b2 − c2)a
Advertisements
उत्तर
(a2 − b2) c + (b2 − c2)a
Step 1: Write down the expression
(a2 − b2) c + (b2 − c2)a
Step 2: Use the difference of squares formula
x2 − y2 = (x − y)(x + y)
So,
a2 − b2 = (a − b)(a + b)
and
b2 − c2 = (b − c)(b + c)
Substitute these into the given expression:
= (a − b)(a + b)c + (b − c)(b + c)a
Step 3: Expand both terms
= c(a2 − b2) + a(b2 − c2)
Simplify by removing brackets:
= a2c − b2c + ab2 − ac2
Step 4: Group terms for common factors
Group as:
= (a2c − ac2) + (ab2 − b2c)
Step 5: Factor each group
From the first group, factor out a c:
ac(a − c)
From the second group, factor out b2:
b2(a − c)
Now the expression becomes:
= ac(a − c) + b2(a − c)
Step 6: Factor out the common term (a−c)
= (a − c)(ac + b2)
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : y2 - (a + b) y + ab
Factorise using the grouping method :
x (6x - 5y) - 4 (6x - 5y)2
Factorise : ab - 2b + a2 - 2a
Factorise : 6a2 - 3a2b - bc2 + 2c2
Factorise : ab(c2 + d2) - a2cd - b2cd
factorise: a2 - 23a -108
factorise: x(3x + 14) + 8
Factorise the following by grouping the terms:
x(x - 4)- x + 4
Factorise the following by grouping the terms:
xy(a2 + 1) + a(x2 + y2)
Factorise the following by grouping the terms:
p2x2 + (px2 + 1)x + p
