Advertisements
Advertisements
प्रश्न
Factorise by the grouping method :
`a^2 + 1/a^2 - 2 - 3a + 3/a`
बेरीज
Advertisements
उत्तर
`a^2 + 1/a^2 - 2 - 3a + 3/a`
= `( a - 1/a )^2 - 3( a - 1/a )`
= `( a - 1/a )[( a - 1/a ) - 3]`
= `( a - 1/a )[ a - 1/a - 3]`
shaalaa.com
Factorisation by Grouping
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise : a2 + ax + ab + bx
Factorise : x2 - (b - 2)x - 2b
Factorise : a(b − c) − d(c − b)
Factorise : ab2 - (a - c) b - c
Factorise : ab(c2 + d2) - a2cd - b2cd
factorise: a2 − 3a − 40
Factorise: 7b2 - 8b + 1
factorise: 3a2x - bx + 3a2 - b
Factorise the following by grouping the terms:
15x2 + 7y - 3x - 35xy
Factorise the following by grouping the terms:
8x3 - 24x2y + 54xy2 -162y3
