Advertisements
Advertisements
प्रश्न
Factorise by the grouping method :
`a^2 + 1/a^2 - 2 - 3a + 3/a`
योग
Advertisements
उत्तर
`a^2 + 1/a^2 - 2 - 3a + 3/a`
= `( a - 1/a )^2 - 3( a - 1/a )`
= `( a - 1/a )[( a - 1/a ) - 3]`
= `( a - 1/a )[ a - 1/a - 3]`
shaalaa.com
Factorisation by Grouping
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : a4 - 2a3 - 4a + 8
Factorise by the grouping method:
ab (x2 + 1) + x (a2 + b2)
Factorise : a3 -a2 +a -1
Factorise : (a2 − b2) c + (b2 − c2)a
factorise: x2 + 5xy + 4y2
factorise: 5 + 3a - 14a2
factorise: 8 + 6(a + b) - 5(a + b)2
factorise: 15(5x - 4)2 - 10(5x - 4)
Factorise the following by grouping the terms:
x(x - 4)- x + 4
Factorise the following by grouping the terms:
`(1)/(25x^2) + 16x^2 + (8)/(5) - 12x - (3)/(5x)`
