Advertisements
Advertisements
प्रश्न
Factorise : ab2 - (a - c) b - c
योग
Advertisements
उत्तर
ab2 - (a - c) b - c
= ab2 - ab + bc - c
= ab (b - 1) + c (b - 1)
= (b - 1) (ab + c)
shaalaa.com
Factorisation by Grouping
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : a3 + a - 3a2 - 3
Factorize using the grouping method:
x2 + y2 + x + y + 2xy
Factorise : a2 - ab - ca + bc
Factorise : 2ab2 - aby + 2cby - cy2
Factorise : ax + 2bx + 3cx - 3a - 6b - 9c
factorise: 2a2 - 17ab + 26b2
factorise: 2x2 + xy - 6y2
factorise: 12(a + b)2 - (a+ b) - 35
Factorise the following by grouping the terms:
2a + b + 3c - d + (2a + b)3 + (2a + b)2(3c - d)
Factorise the following by grouping the terms:
`"p"^2 + (1)/"p"^2 - 2 - 5"p" + (5)/"p"`
