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प्रश्न
Factorise : ab(c2 + d2) - a2cd - b2cd
योग
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उत्तर
ab(c2 + d2) - a2cd - b2cd
= abc2 + abd2 - a2cd - b2cd
= abc2 - a2cd - b2cd + abd2
= ac (bc - ad) - bd (bc - ad)
= (bc - ad) (ac - bd)
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Factorisation by Grouping
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