Advertisements
Advertisements
प्रश्न
Factorise : ab(c2 + d2) - a2cd - b2cd
योग
Advertisements
उत्तर
ab(c2 + d2) - a2cd - b2cd
= abc2 + abd2 - a2cd - b2cd
= abc2 - a2cd - b2cd + abd2
= ac (bc - ad) - bd (bc - ad)
= (bc - ad) (ac - bd)
shaalaa.com
Factorisation by Grouping
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : a2 + b - ab - a
Factorise using the grouping method :
x (6x - 5y) - 4 (6x - 5y)2
Factorise : x2 - (b - 2)x - 2b
Factorise : (a2 − b2) c + (b2 − c2)a
factorise: x2 + 4x + 3
factorise: a2 + 5a + 6
factorise: 2a2 + 7a + 6
factorise: 4 + y - 14y2
Factorise the following by grouping the terms:
8x3 - 24x2y + 54xy2 -162y3
Factorise the following by grouping the terms:
x2 - (p + q)x + pq
