Advertisements
Advertisements
प्रश्न
factorise: 3a2x - bx + 3a2 - b
योग
Advertisements
उत्तर
3a2x - bx + 3a2 - b
= x(3a2 - b) + 1 (3a2 - b)
= (x + 1)(3a2 - b)
shaalaa.com
Factorisation by Grouping
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method: 16 (a + b)2 - 4a - 4b
Factorise using the grouping method :
x (6x - 5y) - 4 (6x - 5y)2
Factorise : ab(c2 + d2) - a2cd - b2cd
factorise: 1 − (2x + 3y) − 6(2x + 3y)2
factorise: 8 + 6(a + b) - 5(a + b)2
factorise: 1 - 18x - 63x2
factorise: 5x2 - 4xy - 12y2
factorise: (3x - 2y)2 - 5(3x - 2y) - 24
factorise: ax2 + b2y - ab2 - x2y
Factorise the following by grouping the terms:
`"p"^2 + (1)/"p"^2 - 2 - 5"p" + (5)/"p"`
