Factorise: 3a2x - Bx + 3a2 - B

factorise: 3a²x - bx + 3a² - b

योग

3a²x - bx + 3a² - b

= x(3a² - b) + 1 (3a² - b)

= (x + 1)(3a² - b)

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Factorisation by Grouping

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अध्याय 13: Factorisation - Exercise 13 (F) [पृष्ठ १६३]

अध्याय 13 Factorisation
Exercise 13 (F) | Q 5.2 | पृष्ठ १६३

Factorise using the grouping method :
a² + 4b² - 3a + 6b - 4ab

Factorise using the grouping method :
m (x - 3y)² + n (3y - x) + 5x - 15y

Factorise : ab² - (a - c) b - c

Factorise : ax + 2bx + 3cx - 3a - 6b - 9c

factorise: 2x² + xy - 6y²

factorise: 5 + 3a - 14a²

factorise: (x - 2y)² - 12(x - 2y) + 32

factorise: a² - 23a -108

Factorise the following by grouping the terms:
3ax² - 5bx² + 9az² + 6ay² - 10by² - 15bz²

Factorise the following by grouping the terms:

`(1)/(25x^2) + 16x^2 + (8)/(5) - 12x - (3)/(5x)`