Advertisements
Advertisements
प्रश्न
Factorise : x2 - (b - 2)x - 2b
योग
Advertisements
उत्तर
x2 - (b - 2)x - 2b
= x2 - bx + 2x - 2b
= x (x - b) + 2(x - b)
= (x - b) (x + 2)
shaalaa.com
Factorisation by Grouping
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : y2 - (a + b) y + ab
Factorise : ab - 2b + a2 - 2a
Factorise : a3 -a2 +a -1
Factorise: 7b2 - 8b + 1
factorise: 5 + 3a - 14a2
factorise: 1 − (2x + 3y) − 6(2x + 3y)2
factorise: (x - 2y)2 - 12(x - 2y) + 32
factorise: 8 + 6(a + b) - 5(a + b)2
factorise: b(c - d)2 + a(d - c) + 3(c - d)
Factorise the following by grouping the terms:
3ax2 - 5bx2 + 9az2 + 6ay2 - 10by2 - 15bz2
