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प्रश्न
Factorise : a(b − c) − d(c − b)
योग
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उत्तर
a(b − c) −d(c − b)
Notice that (c − b) = − (b − c). Substituting this into the expression, we get:
a(b − c) −d(c − b) = a(b − c) −d(−1)(b − c)
Simplify: a(b − c) +d(b − c)
a(b − c) +d(b − c) = (b − c)(a + d)
(b − c)(a + d)
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Factorisation by Grouping
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