Advertisements
Advertisements
प्रश्न
Factorise : a(b − c) − d(c − b)
योग
Advertisements
उत्तर
a(b − c) −d(c − b)
Notice that (c − b) = − (b − c). Substituting this into the expression, we get:
a(b − c) −d(c − b) = a(b − c) −d(−1)(b − c)
Simplify: a(b − c) +d(b − c)
a(b − c) +d(b − c) = (b − c)(a + d)
(b − c)(a + d)
shaalaa.com
Factorisation by Grouping
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : y2 - (a + b) y + ab
Factorise : x2 - (a - 3)x - 3a
Factorise : x2 - (b - 2)x - 2b
Factorise : ab2 - (a - c) b - c
factorise: 14x2 + x - 3
factorise: 1 − (2x + 3y) − 6(2x + 3y)2
factorise: (x - 2y)2 - 12(x - 2y) + 32
factorise: 8 + 6(a + b) - 5(a + b)2
Factorise the following by grouping the terms:
8(2a + b)2 - 8a -4b
Factorise the following by grouping the terms:
9x3 + 6x2y2 - 4y3 - 6xy
