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प्रश्न
factorise: 5x2 - 4xy - 12y2
योग
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उत्तर
5x2 - 4xy - 12y2
= 5x2 - 10xy + 6xy - 12y2
= 5x (x - 2y) + 6y (x - 2y)
= (x - 2y)(5x + 6y)
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Factorisation by Grouping
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संबंधित प्रश्न
Factorise using the grouping method :
a2 + 4b2 - 3a + 6b - 4ab
Factorise : x2 - (b - 2)x - 2b
Factorise : 2ab2c - 2a + 3b3c - 3b - 4b2c2 + 4c
factorise: x2 + 6x + 8
factorise: a2 - 5a+ 6
factorise: a2 − 3a − 40
factorise: 8 + 6(a + b) - 5(a + b)2
factorise: a2 - 23a -108
factorise: 12(a + b)2 - (a+ b) - 35
Factorise the following by grouping the terms:
8(2a + b)2 - 8a -4b
