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प्रश्न
factorise: b(c - d)2 + a(d - c) + 3(c - d)
योग
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उत्तर
b(c - d)2 + a(d - c) + 3(c - d)
= b (c - d)2 - a(c - d) + 3(c - d)
= (c - d) [b (c - d) - a + 3]
= (c - d) (bc - bd - a + 3)
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Factorisation by Grouping
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