Factorise by the Grouping Method: A4 - 2a3 - 4a + 8

Factorise by the grouping method : a⁴ - 2a³ - 4a + 8

योग

a⁴ - 2a³ - 4a + 8 = a³( a - 2 ) - 4( a - 2 )
= ( a³ - 4 )( a - 2 )

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Factorisation by Grouping

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अध्याय 5: Factorisation - Exercise 5 (A) [पृष्ठ ६९]

अध्याय 5 Factorisation
Exercise 5 (A) | Q 7 | पृष्ठ ६९

Factorise : (a² − b²) c + (b² − c²)a

Factorise : ab(c² + d²) - a²cd - b²cd

factorise: 4 + y - 14y²

factorise: 8 + 6(a + b) - 5(a + b)²

Factorise the following by grouping the terms:
15xy - 9x - 25y + 15

Factorise the following by grouping the terms:
x(x - 4)- x + 4

Factorise the following by grouping the terms:
9x³ + 6x²y² - 4y³ - 6xy

Factorise the following by grouping the terms:
xy(a² + 1) + a(x² + y²)

Factorise the following by grouping the terms:
x² - (p + q)x + pq

Factorise the following by grouping the terms:

`"p"^2 + (1)/"p"^2 - 2 - 5"p" + (5)/"p"`