Factorise the Following by Grouping the Terms: P2x2 + (Px2 + 1)X + P - Mathematics

Factorise the following by grouping the terms:
p²x² + (px² + 1)x + p

योग

p²x² + (px² + 1)x + p
= p²x² + px³ + x + p
= (p²x² + px³) + (p + x)
= px²(p + x) + 1(p + x)
= (p + x)(px² + 1).

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Factorisation by Grouping

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अध्याय 5: Factorisation - Exercise 5.1

अध्याय 5 Factorisation
Exercise 5.1 | Q 2.13

Factorise by the grouping method : a (a -4) - a + 4

Factorise : 3x⁵ - 6x⁴ - 2x³ + 4x² + x - 2

Factorise : a³ - a² - ab + a + b - 1

factorise: 2x² + xy - 6y²

factorise: x²y² - 3xy - 40

Factorise the following by grouping the terms:
x(x - 4)- x + 4

Factorise the following by grouping the terms:
3ax² - 5bx² + 9az² + 6ay² - 10by² - 15bz²

Factorise the following by grouping the terms:
2a + b + 3c - d + (2a + b)³ + (2a + b)²(3c - d)

Factorise the following by grouping the terms:

`"p"^2 + (1)/"p"^2 - 2 - 5"p" + (5)/"p"`

Factorise the following by grouping the terms:

`(1)/(25x^2) + 16x^2 + (8)/(5) - 12x - (3)/(5x)`