Advertisements
Advertisements
प्रश्न
Factorise the following by grouping the terms:
9x3 + 6x2y2 - 4y3 - 6xy
योग
Advertisements
उत्तर
9x3 + 6x2y2 - 4y3 - 6xy|
= 9x3 + 6x2y2 - 6xy - 4y3
= (9x3 + 6x2y2) - (6xy + 4y3)
= 3x2(3x + 2y2) - 2y(3x + 2y2)
= (3x + 2y2)(3x2 - 2y).
shaalaa.com
Factorisation by Grouping
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : a3 + a - 3a2 - 3
Factorise : 3x5 - 6x4 - 2x3 + 4x2 + x - 2
factorise: x2 + 5xy + 4y2
factorise: 6 + 7b - 3b2
factorise: 5x2 - 4xy - 12y2
factorise: x(3x + 14) + 8
factorise: (3x - 2y)2 - 5(3x - 2y) - 24
factorise: 15(5x - 4)2 - 10(5x - 4)
Factorise the following by grouping the terms:
2a + b + 3c - d + (2a + b)3 + (2a + b)2(3c - d)
Factorise the following by grouping the terms:
xy(a2 + 1) + a(x2 + y2)
