Advertisements
Advertisements
प्रश्न
Factorise the following by grouping the terms:
9x3 + 6x2y2 - 4y3 - 6xy
योग
Advertisements
उत्तर
9x3 + 6x2y2 - 4y3 - 6xy|
= 9x3 + 6x2y2 - 6xy - 4y3
= (9x3 + 6x2y2) - (6xy + 4y3)
= 3x2(3x + 2y2) - 2y(3x + 2y2)
= (3x + 2y2)(3x2 - 2y).
shaalaa.com
Factorisation by Grouping
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise using the grouping method :
x (6x - 5y) - 4 (6x - 5y)2
Factorise : a2 + ax + ab + bx
Factorise : xy - ay - ax + a2 + bx - ab
Factorise : x2 - (b - 2)x - 2b
Factorise : ab2 - (a - c) b - c
Factorise : 2ab2 - aby + 2cby - cy2
factorise: a2 - 5a+ 6
factorise: a2 - 23a + 42
factorise: 5x2 - 4xy - 12y2
Factorise the following by grouping the terms:
9 + 3xy + x2y + 3x
