Factorise: 14x2 + X - 3

factorise: 14x² + x - 3

बेरीज

14x² + x - 3

= 14x² + 7x - 6x - 3

= 7x (2x + 1) - 3(2x + 1)

= (2x + 1) (7x - 3)

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Factorisation by Grouping

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पाठ 13: Factorisation - Exercise 13 (D) [पृष्ठ १६१]

पाठ 13 Factorisation
Exercise 13 (D) | Q 16 | पृष्ठ १६१

Factorise by the grouping method : ab - 2b + a² - 2a

Factorise using the grouping method :
a² + 4b² - 3a + 6b - 4ab

Factorise : 2ab²c - 2a + 3b³c - 3b - 4b²c² + 4c

factorise: 5 + 3a - 14a²

factorise: (2a + b)² + 5(2a + b) + 6

factorise: 12(a + b)² - (a+ b) - 35

Factorise the following by grouping the terms:
x(x - 4)- x + 4

Factorise the following by grouping the terms:
4abx² + 49aby² + 14xy(a² + b²)

Factorise the following by grouping the terms:

`"p"^2 + (1)/"p"^2 - 2 - 5"p" + (5)/"p"`

Factorise the following by grouping the terms:

`(1)/(25x^2) + 16x^2 + (8)/(5) - 12x - (3)/(5x)`