Factorise: 14x2 + X - 3

factorise: 14x² + x - 3

बेरीज

14x² + x - 3

= 14x² + 7x - 6x - 3

= 7x (2x + 1) - 3(2x + 1)

= (2x + 1) (7x - 3)

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Factorisation by Grouping

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पाठ 13: Factorisation - Exercise 13 (D) [पृष्ठ १६१]

पाठ 13 Factorisation
Exercise 13 (D) | Q 16 | पृष्ठ १६१

Factorise by the grouping method:

ab (x² + 1) + x (a² + b²)

Factorise by the grouping method : (ax + by)² + (bx - ay)²

Factorise : a² - ab - ca + bc

Factorise : ab - 2b + a² - 2a

Factorise : 2ab²c - 2a + 3b³c - 3b - 4b²c² + 4c

factorise: x² + 5xy + 4y²

factorise: 3a² - 5a + 2

Factorise the following by grouping the terms:
x(x - 4)- x + 4

Factorise the following by grouping the terms:
4abx² + 49aby² + 14xy(a² + b²)

Factorise the following by grouping the terms:
2a + b + 3c - d + (2a + b)³ + (2a + b)²(3c - d)