Advertisements
Advertisements
Question
Factorise using the grouping method :
x (6x - 5y) - 4 (6x - 5y)2
Sum
Advertisements
Solution
x (6x - 5y) - 4 (6x - 5y)2
= (6x - 5y) [x - 4(6x - 5y)]
[Taking (6x - 5y) common from the three terms]
= (6x - 5y) (x - 24x + 20y)
= (6x - 5y) (-23x + 20y)
= (6x - 5y) (20y - 23x)
shaalaa.com
Factorisation by Grouping
Is there an error in this question or solution?
