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प्रश्न
Factorise using the grouping method :
x (6x - 5y) - 4 (6x - 5y)2
बेरीज
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उत्तर
x (6x - 5y) - 4 (6x - 5y)2
= (6x - 5y) [x - 4(6x - 5y)]
[Taking (6x - 5y) common from the three terms]
= (6x - 5y) (x - 24x + 20y)
= (6x - 5y) (-23x + 20y)
= (6x - 5y) (20y - 23x)
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Factorisation by Grouping
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
