Advertisements
Advertisements
प्रश्न
Factorise using the grouping method :
m (x - 3y)2 + n (3y - x) + 5x - 15y
बेरीज
Advertisements
उत्तर
m (x - 3y)2 + n (3y - x) + 5x - 15y
= m (x - 3y)2 - n (x - 3y) + 5(x - 3y)
[Taking (x - 3y) common from all the three terms]
= (x - 3y) [m(x - 3y) - n + 5]
= (x - 3y)(mx - 3my - n + 5)
shaalaa.com
Factorisation by Grouping
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : (ax + by)2 + (bx - ay)2
Factorise by the grouping method : a (a -4) - a + 4
Factorise by the grouping method :
`a^2 + 1/a^2 - 2 - 3a + 3/a`
Factorise using the grouping method :
a2 + 4b2 - 3a + 6b - 4ab
Factorise : (a2 − b2) c + (b2 − c2)a
factorise: x2 + 6x + 8
factorise: a2 + 5a + 6
factorise: a2 − 3a − 40
factorise: 8 + 6(a + b) - 5(a + b)2
factorise: ax2 + b2y - ab2 - x2y
