Factorise : Ax + 2bx + 3cx - 3a - 6b - 9c

Factorise : ax + 2bx + 3cx - 3a - 6b - 9c

Sum

ax + 2bx + 3cx - 3a - 6b - 9c

= x (a + 2b + 3c) - 3 (a + 2b + 3c)

= (a + 2b + 3c) (x - 3)

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Factorisation by Grouping

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Chapter 13: Factorisation - Exercise 13 (B) [Page 158]

Chapter 13 Factorisation
Exercise 13 (B) | Q 19 | Page 158

Factorise by the grouping method:

ab (x² + 1) + x (a² + b²)

Factorise by the grouping method : a (a -4) - a + 4

Factorise using the grouping method :
a² + 4b² - 3a + 6b - 4ab

Factorise : 3x⁵ - 6x⁴ - 2x³ + 4x² + x - 2

Factorise : (a² − b²) c + (b² − c²)a

Factorise : ab(c² + d²) - a²cd - b²cd

factorise: 2a² + 7a + 6

factorise: 2x² + xy - 6y²

factorise: ax² + b²y - ab² - x²y

Factorise the following by grouping the terms:

`(1)/(25x^2) + 16x^2 + (8)/(5) - 12x - (3)/(5x)`