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प्रश्न
Factorise : ax + 2bx + 3cx - 3a - 6b - 9c
योग
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उत्तर
ax + 2bx + 3cx - 3a - 6b - 9c
= x (a + 2b + 3c) - 3 (a + 2b + 3c)
= (a + 2b + 3c) (x - 3)
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Factorisation by Grouping
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