Factorise : Ax + 2bx + 3cx - 3a - 6b - 9c - Mathematics

Factorise : ax + 2bx + 3cx - 3a - 6b - 9c

योग

ax + 2bx + 3cx - 3a - 6b - 9c

= x (a + 2b + 3c) - 3 (a + 2b + 3c)

= (a + 2b + 3c) (x - 3)

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Factorisation by Grouping

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अध्याय 13: Factorisation - Exercise 13 (B) [पृष्ठ १५८]

अध्याय 13 Factorisation
Exercise 13 (B) | Q 19 | पृष्ठ १५८

Factorise by the grouping method : (ax + by)² + (bx - ay)²

Factorise by the grouping method : y² - (a + b) y + ab

Factorise using the grouping method :
m (x - 3y)² + n (3y - x) + 5x - 15y

Factorise : a³ -a² +a -1

factorise: x² - x - 72

factorise: 3a²x - bx + 3a² - b

Factorise the following by grouping the terms:
15x² + 7y - 3x - 35xy

Factorise the following by grouping the terms:
9 + 3xy + x²y + 3x

Factorise the following by grouping the terms:
2m³ - 5n² - 5m²n + 2mn

Factorise the following by grouping the terms:

`"p"^2 + (1)/"p"^2 - 2 - 5"p" + (5)/"p"`