Advertisements
Advertisements
Question
factorise: 1 − (2x + 3y) − 6(2x + 3y)2
Sum
Advertisements
Solution
1 − (2x + 3y) − 6(2x + 3y)2
Let (2x + 3y) = a
∴ (2x + 3y)2 = a2
∴ 1 − (2x + 3y) − 6(2x + 3y)2
= 1 − a − 6a2
= 1 − 3a + 2a − 6a2
= 1(1 − 3a) + 2a (1 − 3a)
= (1 − 3a) (1 + 2a)
= [1 − 3 (2x + 3y)] [1 + 2(2x + 3y)]
(Substituting the value of a)
= (1 − 6x − 9y) (1 + 4x + 6y)
shaalaa.com
Factorisation by Grouping
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise using the grouping method :
x (6x - 5y) - 4 (6x - 5y)2
Factorise : a2 + ax + ab + bx
Factorise:
2a − 4b − xa + 2bx
Factorise : 3x5 - 6x4 - 2x3 + 4x2 + x - 2
factorise: a2 +5a - 6
factorise: 2a2 + 7a + 6
factorise: 1 - 18x - 63x2
factorise: b(c - d)2 + a(d - c) + 3(c - d)
Factorise the following by grouping the terms:
2m3 - 5n2 - 5m2n + 2mn
Factorise the following by grouping the terms:
2p(a2 - 2b2) -14p + (a2 - 2b2)2 - 7(a2 - 2b2)
