Advertisements
Advertisements
प्रश्न
factorise: 1 − (2x + 3y) − 6(2x + 3y)2
बेरीज
Advertisements
उत्तर
1 − (2x + 3y) − 6(2x + 3y)2
Let (2x + 3y) = a
∴ (2x + 3y)2 = a2
∴ 1 − (2x + 3y) − 6(2x + 3y)2
= 1 − a − 6a2
= 1 − 3a + 2a − 6a2
= 1(1 − 3a) + 2a (1 − 3a)
= (1 − 3a) (1 + 2a)
= [1 − 3 (2x + 3y)] [1 + 2(2x + 3y)]
(Substituting the value of a)
= (1 − 6x − 9y) (1 + 4x + 6y)
shaalaa.com
Factorisation by Grouping
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : ab - 2b + a2 - 2a
Factorise by the grouping method : (ax + by)2 + (bx - ay)2
Factorise by the grouping method : a (a -4) - a + 4
Factorise : a3 - a2 - ab + a + b - 1
Factorise: 7b2 - 8b + 1
factorise: 14x2 + x - 3
factorise: 6 + 7b - 3b2
factorise: 8 + 6(a + b) - 5(a + b)2
factorise: 1 - 3x - 3y - 4(x + y)2
Factorise the following by grouping the terms:
4abx2 + 49aby2 + 14xy(a2 + b2)
