Advertisements
Advertisements
Question
Factorise : 4x2 - 12ax - y2 - z2 - 2yz + 9a2
Sum
Advertisements
Solution
4x2 - 12ax - y2 - z2 - 2yz + 9a2
= 4x2 + 9a2 - 12ax - y2 - z2 - 2yz
= ( 2x )2 + ( 3a )2 - 12ax - ( y2 + z2 + 2yz )
= ( 2x - 3a )2 - ( y + z )2
= [( 2x - 3a ) - ( y + z )][( 2x - 3a ) + ( y + z )]
[ ∵ a2 - b2 = ( a + b )( a - b )]
= [ 2x - 3a - y - z ][ 2x - 3a + y + z ]
shaalaa.com
Method of Factorisation : Difference of Two Squares
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise : a2 - (2a + 3b)2
Factorise : 4a2b - 9b3
Factorise: 4a2 - (4b2 + 4bc + c2)
Factorise : (x2 + 4y2 - 9z2)2 - 16x2y2
Factorise : `4x^2 + 1/(4x)^2 + 1`
Factorise : 4x4 - x2 - 12x - 36
Factorise the following by the difference of two squares:
(x - 2y)2 -z2
Factorise the following:
9(a - b)2 - (a + b)2
Factorise the following:
4xy - x2 - 4y2 + z2
Express each of the following as the difference of two squares:
(x2 - 2x + 3) (x2 - 2x - 3)
