Advertisements
Advertisements
Question
Factorise : a2 + b2 - c2 - d2 + 2ab - 2cd
Advertisements
Solution
a2 + b2 - c2 - d2 + 2ab - 2cd
= ( a2 + b2 + 2ab ) - ( c2 + d2 + 2cd )
= ( a + b )2 - ( c + d )2
= [( a + b ) - ( c + d )][( a + b ) + ( c + d )] [∵ a2 - b2 = ( a + b )( a - b )]
= ( a + b - c - d )( a + b + c + d )
APPEARS IN
RELATED QUESTIONS
Factorise : a2 - 81 (b-c)2
Factorise : a3 + 2a2 - a - 2
Factorise the following by the difference of two squares:
64x2 - 121y2
Factorise the following by the difference of two squares:
625 - b2
Factorise the following by the difference of two squares:
a(a - 1) - b(b - 1)
Factorise the following by the difference of two squares:
(x + y)2 -1
Factorise the following:
25(x - y)2 - 49(c - d)2
Factorise the following:
b2 - 2bc + c2 - a2
Factorise the following:
`x^2 + (1)/x^2 - 2`
Express each of the following as the difference of two squares:
(x2 - 2x + 3) (x2 - 2x - 3)
