Advertisements
Advertisements
प्रश्न
Factorise : a2 + b2 - c2 - d2 + 2ab - 2cd
बेरीज
Advertisements
उत्तर
a2 + b2 - c2 - d2 + 2ab - 2cd
= ( a2 + b2 + 2ab ) - ( c2 + d2 + 2cd )
= ( a + b )2 - ( c + d )2
= [( a + b ) - ( c + d )][( a + b ) + ( c + d )] [∵ a2 - b2 = ( a + b )( a - b )]
= ( a + b - c - d )( a + b + c + d )
shaalaa.com
Method of Factorisation : Difference of Two Squares
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise : 25(2a - b)2 - 81b2
Factorise : 3a5 - 108a3
Factorise : a4 - 1
Factorise : 4a2 - 12a + 9 - 49b2
Factorise : 4x2 - 12ax - y2 - z2 - 2yz + 9a2
Factorise the following by the difference of two squares:
x2 - 16
Factorise the following by the difference of two squares:
(x + y)2 -1
Factorise the following:
(2a - b)2 -9(3c - d)2
Factorise the following:
4x2 - 12ax - y2 - z2 - 2yz + 9a2
Express each of the following as the difference of two squares:
(x2 + 2x - 3) (x2 - 2x + 3)
