Advertisements
Advertisements
Question
Express the following as a rational number of the form \[\frac{p}{q},\] where p and q are integers and q ≠ 0.
\[\frac{1}{3^{- 2}}\]
Sum
Advertisements
Solution
We know that
\[a^{- n} = \frac{1}{a^n}\]
`1/(3^(-2))=3^2=9`
`1/(3^(-2))=3^2=9`
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Simplify and express the result in power notation with positive exponent.
(−4)5 ÷ (−4)8
Find the value of `{((-2)/3)^(-2)}^2`
Simplify:
\[\left( 4^{- 1} \times 3^{- 1} \right)^2\]
Evaluate:
(−3)−2
Simplify:
\[\left( 3^2 - 2^2 \right) \times \left( \frac{2}{3} \right)^{- 3}\]
\[\left( \frac{2}{3} \right)^{- 5}\] is equal to
\[\left( \frac{- 3}{2} \right)^{- 1}\] is equal to
For any two rational numbers a and b, a5 × b5 is equal to
Find the multiplicative inverse of the following.
2– 4
The cells of a bacteria double itself every hour. How many cells will there be after 8 hours, if initially we start with 1 cell. Express the answer in powers.
