Advertisements
Advertisements
Question
Find the value of (3−1 + 4−1 + 5−1)0
Advertisements
Solution
(3−1 + 4−1 + 5−1)0
= `(1/3 + 1/4 + 1/5)^0` ...`[∵ a^-m = 1/a^m]`
= `((20 + 15 + 12)/60)^0`
= `(47/60)^0`
= 1 ....[∵ a0 = 1]
APPEARS IN
RELATED QUESTIONS
Simplify.
`(3^(-5) xx 10^(-5) xx 125)/(5^(-7) xx 6^(-5))`
By what number should \[\left( \frac{1}{2} \right)^{- 1}\] be multiplied so that the product may be equal to \[\left( - \frac{4}{7} \right)^{- 1} ?\]
Evaluate:
\[\left( \frac{1}{3} \right)^{- 4}\]
Simplify:
\[\left\{ 5^{- 1} \div 6^{- 1} \right\}^3\]
Express the following rational numbers with a negative exponent:
Express the following rational numbers with a negative exponent:
Square of \[\left( \frac{- 2}{3} \right)\] is
For any two non-zero rational numbers a and b, a4 ÷ b4 is equal to
For a non zero rational number a, (a3)−2 is equal to
Find the multiplicative inverse of the following.
10– 5
