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प्रश्न
Find the value of (3−1 + 4−1 + 5−1)0
बेरीज
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उत्तर
(3−1 + 4−1 + 5−1)0
= `(1/3 + 1/4 + 1/5)^0` ...`[∵ a^-m = 1/a^m]`
= `((20 + 15 + 12)/60)^0`
= `(47/60)^0`
= 1 ....[∵ a0 = 1]
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पाठ 10: Exponents and Powers - EXERCISE 10.1 [पृष्ठ १२६]
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संबंधित प्रश्न
Find the value of the following:
(3−1 + 4−1 + 5−1)0
Find the value of the following:
\[\left( \frac{1}{2} \right)^{- 1} + \left( \frac{1}{3} \right)^{- 1} + \left( \frac{1}{4} \right)^{- 1}\]
Simplify:
\[\left( 4^{- 1} \times 3^{- 1} \right)^2\]
Simplify:
\[\left( 3^{- 1} \times 4^{- 1} \right)^{- 1} \times 5^{- 1}\]
Write the following in exponential form:
\[\left( \frac{3}{2} \right)^{- 1} \times \left( \frac{3}{2} \right)^{- 1} \times \left( \frac{3}{2} \right)^{- 1} \times \left( \frac{3}{2} \right)^{- 1}\]
Simplify:
\[\left\{ 3^{- 1} \times 4^{- 1} \right\}^{- 1} \times 5^{- 1}\]
Find x, if
\[\left( \frac{3}{2} \right)^{- 3} \times \left( \frac{3}{2} \right)^5 = \left( \frac{3}{2} \right)^{2x + 1}\]
Which of the following is not equal to \[\left( \frac{- 3}{5} \right)^4 ?\]
\[\left\{ \left( \frac{1}{3} \right)^2 \right\}^4\] is equal to
\[\left( \frac{2}{3} \right)^{- 5} \times \left( \frac{5}{7} \right)^{- 5}\] is equal to
