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प्रश्न
Find the value of (3−1 + 4−1 + 5−1)0
बेरीज
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उत्तर
(3−1 + 4−1 + 5−1)0
= `(1/3 + 1/4 + 1/5)^0` ...`[∵ a^-m = 1/a^m]`
= `((20 + 15 + 12)/60)^0`
= `(47/60)^0`
= 1 ....[∵ a0 = 1]
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पाठ 10: Exponents and Powers - EXERCISE 10.1 [पृष्ठ १२६]
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संबंधित प्रश्न
Simplify and express the result in power notation with positive exponent.
(−4)5 ÷ (−4)8
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\[\left( 2^{- 1} + 3^{- 1} \right)^{- 1}\]
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\[\left( \frac{1}{3} \right)^{- 4}\]
Simplify:
\[\left( 4^{- 1} - 5^{- 1} \right) \div 3^{- 1}\]
Express the following rational numbers with a negative exponent:
\[3^5\]
Express the following rational numbers with a negative exponent:
\[\left\{ \left( \frac{3}{2} \right)^4 \right\}^{- 3}\]
By what number should 5−1 be multiplied so that the product may be equal to (−7)−1?
Find the value of x for which 52x ÷ 5−3 = 55.
Find the value of (2−1 × 4−1) ÷2−2.
Find the multiplicative inverse of the following.
10– 5
