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प्रश्न
पर्याय
- \[\left( \frac{2}{3} \times \frac{5}{7} \right)^{- 10}\]
- \[\left( \frac{2}{3} \times \frac{5}{7} \right)^{- 5}\]
- \[\left( \frac{2}{3} \times \frac{5}{7} \right)^{25}\]
- \[\left( \frac{2}{3} \times \frac{5}{7} \right)^{- 25}\]
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उत्तर
\[\left( \frac{2}{3} \times \frac{5}{7} \right)^{- 5}\]
We have:
\[\left( \frac{2}{3} \right)^{- 5} \times \left( \frac{5}{7} \right)^{- 5}\] `=(2/3xx5/7)^(-5)` → ((a x b)n = an x bn)
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संबंधित प्रश्न
Simplify and express the result in power notation with positive exponent.
(−4)5 ÷ (−4)8
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`(3^(-5) xx 10^(-5) xx 125)/(5^(-7) xx 6^(-5))`
Simplify:
By what number should \[\left( \frac{1}{2} \right)^{- 1}\] be multiplied so that the product may be equal to \[\left( - \frac{4}{7} \right)^{- 1} ?\]
Write the following in exponential form:
Find x, if
Cube of \[\frac{- 1}{2}\] is
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\[\left( \frac{3}{4} \right)^5 \div \left( \frac{5}{3} \right)^5\] is equal to
Evaluate.
`(8^(-1)xx5^(3))/2^(-4)`
