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Question
Simplify:
\[\left( 2^2 + 3^2 - 4^2 \right) \div \left( \frac{3}{2} \right)^2\]
Sum
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Solution
\[( 2^2 + 3^2 - 4^2 ) \div \left( \frac{3}{2} \right)^2 = (4 + 9 - 16) \times \frac{9}{4}\] `->((a/b)^n=(a^n)/(b^n))`
\[= - 3 \times \frac{4}{9}\] ...(We know that `1/a div 1/b = 1/a xx b/1`)
`-4/3`
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