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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Evaluate the following limits: limx→πsin3xsin2x

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Question

Evaluate the following limits:

`lim_(x -> pi) (sin3x)/(sin2x)`

Sum
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Solution

`lim_(x -> pi) (sin3x)/(sin2x) =  lim_(x -> pi) (3sin x - 4 sin^3 x)/(2sinx cos  x)`

= `lim_(x -> pi) [(3sinx)/(2sinx cosx) - (4sin^3x)/(sinx cosx)]`

= `lim_(x -> pi) [3/(2cosx) - (2sin^2x)/cosx]`

= `lim_(x -> pi) 3/(2cosx) - lim_(x -> pi) (2sin^2x)/cosx`

= `3/(2cospi) - (2sin^2pi)/cospi`

=`3/(2 xx -1) - (2 xx 0)/(-1)`

`lim_(x -> pi) (sin3x)/(sin2x) = - 3/2`

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Chapter 9: Differential Calculus - Limits and Continuity - Exercise 9.4 [Page 118]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 9 Differential Calculus - Limits and Continuity
Exercise 9.4 | Q 20 | Page 118

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