English

Evaluate the following Limits: limx→3[x-3x-2-4-x]

Advertisements
Advertisements

Question

Evaluate the following Limits: `lim_(x -> 3)[(x - 3)/(sqrt(x - 2) - sqrt(4 - x))]`

Sum
Advertisements

Solution

`lim_(x -> 3)[(x - 3)/(sqrt(x - 2) - sqrt(4 - x))]`

= `lim_(x -> 3)[(x - 3)/(sqrt(x - 2) - sqrt(4 - x)) xx(sqrt(x - 2) + sqrt(4 - x))/(sqrt(x - 2) + sqrt(4 - x))]`

= `lim_(x ->3) ((x - 3)(sqrt(x - 2) + sqrt(4 - x)))/((x - 2) - (4 - x)`

= `lim_(x -> 3) ((x - 3)(sqrt(x - 2) + sqrt(4 - x)))/(2x - 6)`

= `lim_(x -> 3) ((x - 3)(sqrt(x - 2) + sqrt(4 - x)))/(2(x - 3)`

= `lim_(x -> 3) (sqrt(x - 2) + sqrt(4 - x))/2   ...[("As"  x -> 3"," x ≠ 3),(therefore x - 3 ≠ 0)]`

= `1/2 lim_(x -> 3)(sqrt(x - 2) + sqrt(4 - x))`

= `1/2(sqrt(3 - 2) + sqrt(4 - 3))`

= `1/2(1 + 1)`

= 1

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Limits - MISCELLANEOUS EXERCISE - 7 [Page 106]

APPEARS IN

RELATED QUESTIONS

Evaluate the following limits: `lim_(x -> 3) [1/(x - 3) - (9x)/(x^3 - 27)]`


Evaluate the following limits: `lim_(x -> 2)[(x^3 - 4x^2 + 4x)/(x^2 - 1)]`


Evaluate the following limit :

`lim_(x -> 2)[(x^3 - 4x^2 + 4x)/(x^2 - 1)]`


Evaluate the following limit :

`lim_(Deltax -> 0) [((x + Deltax)^2 - 2(x + Deltax) + 1 - (x^2 - 2x + 1))/(Deltax)]`


Evaluate the following limit:

`lim_(x -> 1) [(x^4 - 3x^2 + 2)/(x^3 - 5x^2 + 3x + 1)]`


Select the correct answer from the given alternatives.

`lim_(x -> -2)((x^7 + 128)/(x^3 + 8))` =


Select the correct answer from the given alternatives.

`lim_(x -> 3) (1/(x^2 - 11x + 24) + 1/(x^2 - x - 6))` = 


Select the correct answer from the given alternatives.

`lim_(x -> 5) ((sqrt(x + 4) - 3)/(sqrt(3x - 11) - 2))` =


Evaluate the following limits

`lim_(x->-2) [(x^7 + x^5 + 160 )/(x^3 + 8)]`


Evaluate the following limit :

`lim_("x" -> -2) [("x"^7 + "x"^5 + 160)/("x"^3 +8)]`


Evaluate the following Limit.

`lim_(x->1)[(x^3 - 1)/(x^2 + 5x - 6)]`


Evaluate the following limit:

`lim_(z->2)[(z^2 - 5z + 6)/(z^2 - 4)]`


Evaluate the following limit:

`lim_(z->2)[(z^2 - 5z + 6)/(z^2 - 4)]`


Evaluate the following limit:

`lim_(x -> 1)[(x^3 - 1) / (x^2 + 5x - 6)]`


Evaluate the following limit:

`lim_(z->2)[(z^2-5z+6)/(z^2-4)]`


Evaluate the following limit:

`lim_(z->2)[(z^2-5z+6)/(z^2-4)]`


Evaluate the following limit:

`lim_(x->-2) [(x^7 + x^5 +160)/(x^3 + 8)]`


Evaluate the following Limit.

`lim_(x->1)[(x^3-1)/(x^2+5x-6)]`


Evaluate the following limit:

`lim_(x ->1)[(x^3 - 1)/(x^2 + 5x - 6)]`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×