English

Select the correct answer from the given alternatives. limx→2(x4-16x2-5x+6) = - Mathematics and Statistics

Advertisements
Advertisements

Question

Select the correct answer from the given alternatives.

`lim_(x -> 2) ((x^4 - 16)/(x^2 - 5x + 6))` =

Options

  • 23

  • 32

  • – 32

  • – 16

MCQ
Advertisements

Solution

`lim_(x -> 2) ((x^4 - 16)/(x^2 - 5x + 6))` = – 32

shaalaa.com
Factorization Method
  Is there an error in this question or solution?
Chapter 7: Limits - Miscellaneous Exercise 7.1 [Page 158]

APPEARS IN

RELATED QUESTIONS

Evaluate the following limits: `lim_(z -> 2) [(z^2 - 5z + 6)/(z^2 - 4)]`


Evaluate the following limits: `lim_(x -> - 3)[(x + 3)/(x^2 + 4x + 3)]` 


Evaluate the following limits: `lim_(y -> 0)[(5y^3 + 8y^2)/(3y^4 - 16y^2)]`


Evaluate the following limits: `lim_(u -> 1)[(u^4 - 1)/(u^3 - 1)]`


Evaluate the following limits: `lim_(x -> 2)[(x^3 - 4x^2 + 4x)/(x^2 - 1)]`


Evaluate the following limits: `lim_("v" -> sqrt(2))[("v"^2 + "v"sqrt(2) - 4)/("v"^2 - 3"v"sqrt(2) + 4)]`


Evaluate the following limit:

`lim_(x -> 1)[(x^3 - 1)/(x^2 + 5x - 6)]`


Evaluate the following limit :

`lim_(x -> -3)[(x + 3)/(x^2 + 4x + 3)]`


Evaluate the following limit :

`lim_(y -> 0)[(5y^3 + 8y^2)/(3y^4 - 16y^2)]`


Evaluate the following limit :

`lim_(x -> -2) [(-2x - 4)/(x^3 + 2x^2)]`


Evaluate the following limit :

`lim_(u -> 1) [(u^4 - 1)/(u^3 - 1)]`


Evaluate the following limit :

`lim_(Deltax -> 0) [((x + Deltax)^2 - 2(x + Deltax) + 1 - (x^2 - 2x + 1))/(Deltax)]`


Evaluate the following limit :

`lim_(x -> sqrt(2)) [(x^2 + xsqrt(2) - 4)/(x^2 - 3xsqrt(2) + 4)]`


Evaluate the following limit :

`lim_(x -> 2) [(x^3 - 7x + 6)/(x^3 - 7x^2 + 16x - 12)]`


Evaluate the following limit :

`lim_(y -> 1/2) [(1 - 8y^3)/(y - 4y^3)]`


Evaluate the following limit:

`lim_(x -> 1) [(x^4 - 3x^2 + 2)/(x^3 - 5x^2 + 3x + 1)]`


Evaluate the following limit :

`lim_(x -> 1) [(x + 2)/(x^2 - 5x + 4) + (x - 4)/(3(x^2 - 3x + 2))]`


Select the correct answer from the given alternatives.

`lim_(x -> 5) ((sqrt(x + 4) - 3)/(sqrt(3x - 11) - 2))` =


Evaluate the following limits

`lim_(x->-2) [(x^7 + x^5 + 160 )/(x^3 + 8)]`


Evaluate the following

Limit: `lim_(x->1) [(x^3 - 1 )/ (x^2 + 5x -6)]`


Evaluate the following limit:

`lim_(z->2)[(z^2 - 5z + 6)/(z^2 - 4)]`


Evaluate the following limit:

`lim_(x-> -2) [(x^7 + x^5 + 160)/(x^3 + 8)]`


Evaluate the following Limit.

`lim_(x->1)[(x^3 - 1)/(x^2 + 5x - 6)]`


Evaluate the following Limit.

`lim_(x->1)[(x^3 -1)/(x^2 +5x -6)]`


Evaluate the following limit:

`lim_(z->2)[(z^2 - 5z + 6)/(z^2 - 4)]`


Evaluate the following limit:

`lim_(x -> 1)[(x^3 - 1) / (x^2 + 5x - 6)]`


Evaluate the following limits:

`lim_(z→2)[( z^2 - 5 z + 6)/(z ^ 2 - 4)]`


Evaluate the following Limit:

`lim_(x->1)[(x^3-1)/(x^2 + 5x - 6)]`


Evaluate the following limit:

`lim_(x->-2)[(x^7 + x^5 + 160)/(x^3 + 8)]`


Evaluate the following limit:

`\underset{x->2}{lim} [(x^7 + x^5 + 160)/(x^3 +8)]`


Evaluate the following Limit.

`lim_(x->1)[(x^3 - 1)/(x^2 + 5x - 6)]`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×