हिंदी

Select the correct answer from the given alternatives. limx→2(x4-16x2-5x+6) =

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प्रश्न

Select the correct answer from the given alternatives.

`lim_(x -> 2) ((x^4 - 16)/(x^2 - 5x + 6))` =

विकल्प

  • 23

  • 32

  • – 32

  • – 16

MCQ
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उत्तर

`lim_(x -> 2) ((x^4 - 16)/(x^2 - 5x + 6))` = – 32

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अध्याय 7: Limits - Miscellaneous Exercise 7.1 [पृष्ठ १५८]

APPEARS IN

बालभारती Mathematics and Statistics (Arts and Science) Part 2 [English] Standard 11 Maharashtra State Board
अध्याय 7 Limits
Miscellaneous Exercise 7.1 | Q I. (1) | पृष्ठ १५८

संबंधित प्रश्न

Evaluate the following limits: `lim_(z -> 2) [(z^2 - 5z + 6)/(z^2 - 4)]`


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`lim_(x -> - 2)[(x^7 + x^5 + 160)/(x^3 + 8)]`


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`lim_(x -> 3) [(x^2 + 2x - 15)/(x^2 - 5x + 6)]`


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`lim_(x -> 2)[(x^3 - 4x^2 + 4x)/(x^2 - 1)]`


Evaluate the following limit :

`lim_(Deltax -> 0) [((x + Deltax)^2 - 2(x + Deltax) + 1 - (x^2 - 2x + 1))/(Deltax)]`


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`lim_(x -> -2)((x^7 + 128)/(x^3 + 8))` =


Select the correct answer from the given alternatives.

`lim_(x -> 5) ((sqrt(x + 4) - 3)/(sqrt(3x - 11) - 2))` =


Evaluate the following limits

`lim_(x->-2) [(x^7 + x^5 + 160 )/(x^3 + 8)]`


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`lim_("x" -> -2) [("x"^7 + "x"^5 + 160)/("x"^3 +8)]`


Evaluate the following limit:

`lim_(x->-2) [(x^7 + x^5 + 160)/(x^3 + 8)]`


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`lim_(x->1)[(x^3 - 1)/(x^2 + 5x - 6)]`


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`lim_(x->1)[(x^3 -1)/(x^2 +5x -6)]`


Evaluate the following limit:

`lim_(z->2)[(z^2 - 5z + 6)/(z^2 - 4)]`


Evaluate the following limit:

`lim_(x -> 1)[(x^3 - 1) / (x^2 + 5x - 6)]`


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`lim_(x->-2) [(x^7 + x^5 +160)/(x^3 + 8)]`


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`lim_(x->-2) [(x^7 + x^5 +160)/(x^3 + 8)]`


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`lim_(x -> 1)[(x^3 - 1)/(x^2 + 5x - 6)]`


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Evaluate the following limit:

`lim_(x-> -2)[(x^7 + x^5 + 160)/(x^3 +8)]`


Evaluate the following Limit:

`lim_(x->1)[(x^3-1)/(x^2+5x-6)]`


Evaluate the following limit:

`lim_(x ->1)[(x^3 - 1)/(x^2 + 5x - 6)]`


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