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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Select the correct answer from the given alternatives. limx→2(x4-16x2-5x+6) = - Mathematics and Statistics

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प्रश्न

Select the correct answer from the given alternatives.

`lim_(x -> 2) ((x^4 - 16)/(x^2 - 5x + 6))` =

पर्याय

  • 23

  • 32

  • – 32

  • – 16

MCQ
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उत्तर

`lim_(x -> 2) ((x^4 - 16)/(x^2 - 5x + 6))` = – 32

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पाठ 7: Limits - Miscellaneous Exercise 7.1 [पृष्ठ १५८]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 7 Limits
Miscellaneous Exercise 7.1 | Q I. (1) | पृष्ठ १५८

संबंधित प्रश्‍न

Evaluate the following limits: `lim_(x -> - 3)[(x + 3)/(x^2 + 4x + 3)]` 


Evaluate the following limit:

`lim_(x -> - 2)[(x^7 + x^5 + 160)/(x^3 + 8)]`


Evaluate the following limits: `lim_(y -> 1/2)[(1 - 8y^3)/(y - 4y^3)]`


Evaluate the following limits: `lim_("v" -> sqrt(2))[("v"^2 + "v"sqrt(2) - 4)/("v"^2 - 3"v"sqrt(2) + 4)]`


Evaluate the following limits: `lim_(x -> 3)[(x^2 + 2x - 15)/(x^2 - 5x + 6)]`


Evaluate the following limit:

`lim_(z -> 2) [(z^2 - 5z + 6)/(z^2 - 4)]`


Evaluate the following limit :

`lim_(x -> -3)[(x + 3)/(x^2 + 4x + 3)]`


Evaluate the following limit :

`lim_(y -> 0)[(5y^3 + 8y^2)/(3y^4 - 16y^2)]`


Evaluate the following limit :

`lim_(x -> 3) [(x^2 + 2x - 15)/(x^2 - 5x + 6)]`


Evaluate the following limit :

`lim_(y -> 1/2) [(1 - 8y^3)/(y - 4y^3)]`


Evaluate the following limit :

`lim_(x -> 1) [(x - 2)/(x^2 - x) - 1/(x^3 - 3x^2 + 2x)]`


Evaluate the following limit:

`lim_(x -> 1) [(x^4 - 3x^2 + 2)/(x^3 - 5x^2 + 3x + 1)]`


Evaluate the following limit :

`lim_(x -> "a")[1/(x^2 - 3"a"x + 2"a"^2) + 1/(2x^2 - 3"a"x + "a"^2)]`


Select the correct answer from the given alternatives.

`lim_(x -> -2)((x^7 + 128)/(x^3 + 8))` =


Select the correct answer from the given alternatives.

`lim_(x -> 3) (1/(x^2 - 11x + 24) + 1/(x^2 - x - 6))` = 


Evaluate the following limits

`lim_(x->-2) [(x^7 + x^5 + 160 )/(x^3 + 8)]`


Evaluate the following

Limit: `lim_(x->1) [(x^3 - 1 )/ (x^2 + 5x -6)]`


Evaluate the following limit :

`lim_("x" -> -2) [("x"^7 + "x"^5 + 160)/("x"^3 +8)]`


Evaluate the following Limit.

`lim_(x -> 1)[(x^3 - 1)/(x^2 + 5x - 6)]`


Evaluate the following limit:

`lim_(z->2)[(z^2 - 5z + 6)/(z^2 - 4)]`


Evaluate the following limit:

`lim_(x-> -2) [(x^7 + x^5 + 160)/(x^3 + 8)]`


Evaluate the following Limit.

`lim_(x->1)[(x^3 - 1)/(x^2 + 5x - 6)]`


Evaluate the following limit:

`lim_(z->2)[(z^2 - 5z + 6)/(z^2 - 4)]`


Evaluate the following limit:

`lim_(z->2)[(z^2-5z+6)/(z^2-4)]`


Evaluate the following limit:

`lim_(x->-2)[(x^7+x^5+160)/(x^3+8)]`


Evaluate the following limit:

`lim_(z->2)[(z^2-5z+6)/(z^2-4)]`


Evaluate the following limits:

`lim_(z→2)[( z^2 - 5 z + 6)/(z ^ 2 - 4)]`


Evaluate the following limit:

`lim_(x->-2) [(x^7 + x^5 +160)/(x^3 + 8)]`


Evaluate the following Limit.

`lim_(x -> 1)[(x^3 - 1)/(x^2 + 5x - 6)]`


Evaluate the following Limit:

`lim_(x->1)[(x^3-1)/(x^2+5x-6)]`


Evaluate the following limit:

`lim_(x->-2)[(x^7 + x^5 + 160)/(x^3 + 8)]`


Evaluate the following limit:

`\underset{x->2}{lim} [(x^7 + x^5 + 160)/(x^3 +8)]`


Evaluate the following Limit.

`lim_(x->1)[(x^3 - 1)/(x^2 + 5x - 6)]`


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