मराठी

Evaluate the following Limits: limx→3[x-3x-2-4-x]

Advertisements
Advertisements

प्रश्न

Evaluate the following Limits: `lim_(x -> 3)[(x - 3)/(sqrt(x - 2) - sqrt(4 - x))]`

बेरीज
Advertisements

उत्तर

`lim_(x -> 3)[(x - 3)/(sqrt(x - 2) - sqrt(4 - x))]`

= `lim_(x -> 3)[(x - 3)/(sqrt(x - 2) - sqrt(4 - x)) xx(sqrt(x - 2) + sqrt(4 - x))/(sqrt(x - 2) + sqrt(4 - x))]`

= `lim_(x ->3) ((x - 3)(sqrt(x - 2) + sqrt(4 - x)))/((x - 2) - (4 - x)`

= `lim_(x -> 3) ((x - 3)(sqrt(x - 2) + sqrt(4 - x)))/(2x - 6)`

= `lim_(x -> 3) ((x - 3)(sqrt(x - 2) + sqrt(4 - x)))/(2(x - 3)`

= `lim_(x -> 3) (sqrt(x - 2) + sqrt(4 - x))/2   ...[("As"  x -> 3"," x ≠ 3),(therefore x - 3 ≠ 0)]`

= `1/2 lim_(x -> 3)(sqrt(x - 2) + sqrt(4 - x))`

= `1/2(sqrt(3 - 2) + sqrt(4 - 3))`

= `1/2(1 + 1)`

= 1

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Limits - MISCELLANEOUS EXERCISE - 7 [पृष्ठ १०६]

APPEARS IN

बालभारती Mathematics and Statistics (Commerce) Part 1 [English] Standard 11 Maharashtra State Board
पाठ 7 Limits
MISCELLANEOUS EXERCISE - 7 | Q II. 5) | पृष्ठ १०६

संबंधित प्रश्‍न

Evaluate the following limits: `lim_(z -> 2) [(z^2 - 5z + 6)/(z^2 - 4)]`


Evaluate the following Limits: `lim_(x -> 2)[((x - 2))/(2x^2 - 7x + 6)]`


Evaluate the following limit:

`lim_(z -> 2) [(z^2 - 5z + 6)/(z^2 - 4)]`


Evaluate the following limit :

`lim_(x -> -2) [(-2x - 4)/(x^3 + 2x^2)]`


Evaluate the following limit :

`lim_(x -> 2)[(x^3 - 4x^2 + 4x)/(x^2 - 1)]`


Evaluate the following limit :

`lim_(Deltax -> 0) [((x + Deltax)^2 - 2(x + Deltax) + 1 - (x^2 - 2x + 1))/(Deltax)]`


Evaluate the following limit :

`lim_(x -> 2) [(x^3 - 7x + 6)/(x^3 - 7x^2 + 16x - 12)]`


Evaluate the following limit :

`lim_(x -> 1) [(x + 2)/(x^2 - 5x + 4) + (x - 4)/(3(x^2 - 3x + 2))]`


Select the correct answer from the given alternatives.

`lim_(x -> 2) ((x^4 - 16)/(x^2 - 5x + 6))` =


Select the correct answer from the given alternatives.

`lim_(x -> -2)((x^7 + 128)/(x^3 + 8))` =


Select the correct answer from the given alternatives.

`lim_(x -> 5) ((sqrt(x + 4) - 3)/(sqrt(3x - 11) - 2))` =


Evaluate the following

Limit: `lim_(x->1) [(x^3 - 1 )/ (x^2 + 5x -6)]`


Evaluate the following limit:

`lim_(z->2)[(z^2 - 5z + 6)/(z^2 - 4)]`


Evaluate the following limit:

`lim_(z->2)[(z^2 - 5z + 6)/(z^2 - 4)]`


Evaluate the following limits:

`lim_(z→2)[( z^2 - 5 z + 6)/(z ^ 2 - 4)]`


Evaluate the following limit:

`lim_(x->-2) [(x^7 + x^5 +160)/(x^3 + 8)]`


Evaluate the following Limit.

`lim_(x->1)[(x^3-1)/(x^2+5x-6)]`


Evaluate the following limit:

`lim_(x->2) [(z^2 - 5_z + 6)/ (z^2 - 4)]` 


Evaluate the following limit:

`\underset{x->2}{lim} [(x^7 + x^5 + 160)/(x^3 +8)]`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×