Advertisements
Advertisements
प्रश्न
Evaluate the following limits: `lim_(x -> -2)[(-2x - 4)/(x^3 + 2x^2)]`
Advertisements
उत्तर
`lim_(x -> -2)[(-2x - 4)/(x^3 + 2x^2)]`
= `lim_(x -> - 2) (-2(x + 2))/(x^2 (x + 2)`
= `lim_(x -> -2) (-2)/(x^2) ...[("As" x -> - 2"," x ≠ - 2),(therefore x + 2 ≠ 0)]`
= `((-2))/(-2)^2`
= `(-2)/4`
= `(-1)/2`
APPEARS IN
संबंधित प्रश्न
Evaluate the following limits: `lim_(z -> 2) [(z^2 - 5z + 6)/(z^2 - 4)]`
Evaluate the following limits: `lim_(y -> 1/2)[(1 - 8y^3)/(y - 4y^3)]`
Evaluate the following Limits: `lim_(x -> 2)[((x - 2))/(2x^2 - 7x + 6)]`
Evaluate the following limit:
`lim_(z -> 2) [(z^2 - 5z + 6)/(z^2 - 4)]`
Evaluate the following limit :
`lim_(x -> -3)[(x + 3)/(x^2 + 4x + 3)]`
Evaluate the following limit:
`lim_(x -> 1) [(x^4 - 3x^2 + 2)/(x^3 - 5x^2 + 3x + 1)]`
Evaluate the following limit :
`lim_(x->-2)[(x^7 + x^5 +160)/(x^3+8)]`
Evaluate the following
Limit: `lim_(x->1) [(x^3 - 1 )/ (x^2 + 5x -6)]`
Evaluate the following limit:
`lim_(x->-2) [(x^7 + x^5 + 160)/(x^3 + 8)]`
Evaluate the following limit:
`lim_(x-> -2) [(x^7 + x^5 + 160)/(x^3 + 8)]`
Evaluate the following Limit.
`lim_(x->1)[(x^3 -1)/(x^2 +5x -6)]`
Evaluate the following Limit.
`lim_(x->1)[(x^3 -1)/(x^2 +5x -6)]`
Evaluate the following limit:
`lim_(x -> 1)[(x^3 - 1) / (x^2 + 5x - 6)]`
Evaluate the following limit:
`lim_(z->2)[(z^2-5z+6)/(z^2-4)]`
Evaluate the following limit:
`lim_(x->-2)[(x^7+x^5+160)/(x^3+8)]`
Evaluate the following limit:
`lim_(z->2)[(z^2-5z+6)/(z^2-4)]`
Evaluate the following limits:
`lim_(z→2)[( z^2 - 5 z + 6)/(z ^ 2 - 4)]`
Evaluate the following limit:
`lim_(x->2) [(z^2 - 5_z + 6)/ (z^2 - 4)]`
Evaluate the following limit:
`lim_(x-> -2)[(x^7 + x^5 + 160)/(x^3 +8)]`
