English

Evaluate sin25° cos65° + cos25° sin65° - Mathematics

Advertisements
Advertisements

Question

 Evaluate sin25° cos65° + cos25° sin65°

Advertisements

Solution

sin25° cos65° + cos25° sin65°

=(sin 25°) {cos(90°-25°)}+cos 25°{sin(90°-25)}

=(sin 25°)(sin 25°) + (cos 25°)(cos 25°)

= sin225° + cos225°

= 1 (As sin2A + cos2A = 1)

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Introduction to Trigonometry - Exercise 8.4 [Page 193]

APPEARS IN

NCERT Mathematics [English] Class 10
Chapter 8 Introduction to Trigonometry
Exercise 8.4 | Q 3.2 | Page 193

RELATED QUESTIONS

Prove the following trigonometric identities

`cos theta/(1 - sin theta) = (1 + sin theta)/cos theta`


Prove the following trigonometric identities.

`(1 - cos theta)/sin theta = sin theta/(1 + cos theta)`


If cosec2 θ (1 + cos θ) (1 − cos θ) = λ, then find the value of λ. 


 Write True' or False' and justify your answer the following :

The value of the expression \[\sin {80}^° - \cos {80}^°\] 


The value of (1 + cot θ − cosec θ) (1 + tan θ + sec θ) is 


The value of sin ( \[{45}^° + \theta) - \cos ( {45}^°- \theta)\] is equal to 


Prove the following identity :

`(cosA + sinA)^2 + (cosA - sinA)^2 = 2`


Prove the following identity : 

`1/(sinA + cosA) + 1/(sinA - cosA) = (2sinA)/(1 - 2cos^2A)`


Find the value of x , if `cosx = cos60^circ cos30^circ - sin60^circ sin30^circ`


Prove that `sinA/sin(90^circ - A) + cosA/cos(90^circ - A) = sec(90^circ - A) cosec(90^circ - A)`


If sec θ = `25/7`, then find the value of tan θ.


A moving boat is observed from the top of a 150 m high cliff moving away from the cliff. The angle of depression of the boat changes from 60° to 45° in 2 minutes. Find the speed of the boat in m/min.


Prove that : `1 - (cos^2 θ)/(1 + sin θ) = sin θ`.


If tan α = n tan β, sin α = m sin β, prove that cos2 α  = `(m^2 - 1)/(n^2 - 1)`.


a cot θ + b cosec θ = p and b cot θ + a cosec θ = q then p2 – q2 is equal to


Prove that `(tan^2 theta - 1)/(tan^2 theta + 1)` = 1 – 2 cos2θ


To prove cot θ + tan θ = cosec θ × sec θ, complete the activity given below.

Activity:

L.H.S = `square`

= `square/sintheta + sintheta/costheta`

= `(cos^2theta + sin^2theta)/square`

= `1/(sintheta*costheta)`     ......`[cos^2theta + sin^2theta = square]`

= `1/sintheta xx 1/square`

= `square`

= R.H.S


Prove the following:

`tanA/(1 + sec A) - tanA/(1 - sec A)` = 2cosec A


If sinθ – cosθ = 0, then the value of (sin4θ + cos4θ) is ______.


Let x1, x2, x3 be the solutions of `tan^-1((2x + 1)/(x + 1)) + tan^-1((2x - 1)/(x - 1))` = 2tan–1(x + 1) where x1 < x2 < x3 then 2x1 + x2 + x32 is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×