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`((Sin A- Sin B ))/(( Cos a + Cos B ))+ (( Cos a - Cos B ))/(( Sina + Sin B ))=0` - Mathematics

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Question

`((sin A-  sin B ))/(( cos A + cos B ))+ (( cos A - cos B ))/(( sinA + sin B ))=0` 

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Solution

LHS =`((sin A-  sin B ))/(( cos A + cos B ))+ (( cos A - cos B ))/(( sinA + sin B ))` 

     =`((sinA - sin B )( sinA + sinB )+ ( cos A - cosB )( cosA - cosB))/((cos A+ cos B )( sin A+ sinB))`

    =` (sin^2 A - sin^2 B + cos^2 A - cos^2 B)/( (cos A + cos B )( sinA + sinB))`

   =` 0/((cos A + cos B )( sin A + sinB ))`

   =0 

   =RHS

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Chapter 8: Trigonometric Identities - Exercises 1

APPEARS IN

R.S. Aggarwal Mathematics [English] Class 10
Chapter 8 Trigonometric Identities
Exercises 1 | Q 34

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= `square (1 - (sin^2theta)/(tan^2theta))`

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= `tan^2theta (1 - (sin^2theta)/1 xx (cos^2theta)/square)`

= `tan^2theta (1 - square)`

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But `"AB"/"AC" = square and "BC"/"AC" = square`

∴ `sin^2 theta  + cos^2 theta = square` 


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