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Evaluate: (8^2/9^−3)^1/6 - Mathematics

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Question

Evaluate:

`(8^2/9^-3)^(1/6)`

Evaluate
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Solution

Given expression is `(8^2/9^-3)^(1/6)`

We have to evaluate the given expression.

Thus, `(8^2/9^-3)^(1/6)`

⇒ `(8^2)^(1/6)/(9^-3)^(1/6)`  ...`[∴ (a/b)^n = a^n/b^n]`

⇒ `(8^(2 xx 1/6)/(9^(-3 xx 1/6)))`  ...[∴ (an)m = an × m]

⇒ `(8^(1/3)/(9^((-1)/2)))`

⇒ `8^(1/3) xx 9^(1/2)`  ...`[∴ 1/a^-1 = a^1]`

⇒ `(2^3)^(1/3) xx (3^2)^(1/2)`

⇒ `2^(3/3) xx 3^(2/2)`

⇒ (2)1 × (3)1

⇒ 6

Hence, `(8^2/9^-3)^(1/6) = 6`.

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Chapter 6: Indices - EXERCISE 6 [Page 66]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 6 Indices
EXERCISE 6 | Q 1. (vi) | Page 66
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