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Simplify: (36โข๐‘Ž^8)^โˆ’1/2โข (125โข๐‘Ž^15)^1/3 - Mathematics

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Question

Simplify:

`(36a^8)^((-1)/2) (125a^15)^(1/3)`

Simplify
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Solution

Given,

`(36a^8)^((-1)/2) (125a^15)^(1/3)`

We have to simplify the given expression.

Thus, `(36a^8)^((-1)/2) (125a^15)^(1/3)`

⇒ `[(36)^((-1)/2) xx (a^8)^((-1)/2)] xx [(125)^(1/3) xx (a^15)^(1/3)]`  ...[∴ (a × b)n = an × bn]

⇒ `[(6^2)^((-1)/2) xx (a^8)^((-1)/2)] xx [(5^3)^(1/3) xx (a^15)^(1/3)]`  ...[∴ (an)m = anm]

⇒ `[(6)^-1 xx (a^-4)] xx [(5)^1 xx (a^5)]`

⇒ `1/6 xx 5 xx (a^5) xx (a^-4)` ...`[∴ 1/a^n = a^-n]`

⇒ `5/6 xx a^(5 - 4)`   ...[∴ (an × am) = an + m]

⇒ `(5a)/6`

Hence, `(36a^8)^((-1)/2) (125a^15)^(1/3) = (5a)/6`.

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Chapter 6: Indices - EXERCISE 6 [Page 66]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 6 Indices
EXERCISE 6 | Q 2. (i) | Page 66
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