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Question
Equal heat is given to two objects A and B of mass 1 g. Temperature of A increases by 3°C and B by 5°C. Which object has more specific heat? And by what factor?
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Solution
`s = (DeltaQ)/(mDeltaT)`
Let Q cal of heat be given to both A and B.
For body A,
`s_1 = Q/(1 xx 3) = Q/3 "cal" g^(-1@)C^(-1)`
For body B,
`s_2 = Q/(1 xx 5) = Q/5 "cal" g^(-1@)C^(-1)`
Now,
`(s_1)/(s_2) = (Q/3)/(Q/5) = 5/3`
= `s_1 = 5/3 s_2`
Thus, specific heat capacity of body A is more than body B and by a factor of `5/3`.
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