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Maharashtra State BoardSSC (English Medium) 7th Standard

Draw triangle with the measures given below. In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm - Mathematics

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Question

Draw triangle with the measures given below.

In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm 

Geometric Constructions
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Solution

Steps of construction:

  1. Draw a line PQ = 6 cm.
  2. With P as centre and 4.5 cm as the radius, draw an arc above the line PQ.
  3. With Q as the center and 3.8 cm as the radius, draw an arc cutting the previous drawn arc at point R.
  4. Join RP and RQ.
ΔPQR is thus the required triangle. 
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Chapter 1: Geometrical Constructions - Practice Set 2 [Page 4]

APPEARS IN

Balbharati Mathematics [English] Standard 7 Maharashtra State Board
Chapter 1 Geometrical Constructions
Practice Set 2 | Q 1.3 | Page 4
Balbharati Mathematics Integrated [English] Standard 7 Maharashtra State Board
Chapter 1 Geometrical Constructions
Practice Set 2 | Q 1. (c) | Page 41

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