Advertisements
Advertisements
Question
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Advertisements
Solution
Steps of construction:
- Draw a line PQ = 6 cm.
- With P as centre and 4.5 cm as the radius, draw an arc above the line PQ.
- With Q as the center and 3.8 cm as the radius, draw an arc cutting the previous drawn arc at point R.
- Join RP and RQ.
RELATED QUESTIONS
In ∆ STU, l(ST) = 7 cm, l(TU) = 4 cm, l(SU) = 5 cm
Draw an isosceles triangle with base 5 cm and the other sides 3.5 cm each.
Draw an equilateral triangle with side 6.5 cm.
Draw triangle with the measures given below.
In ∆FUN, l(FU) = 5 cm, l(UN) = 4.6 cm, m∠U = 110°
Construct ∆EFG from the given measures. l(FG) = 5 cm, m∠EFG = 90°, l(EG) = 7 cm.
Construct a triangle using the given data: DE = 5cm, ∠D = 75° and ∠E = 60°
Construct a right-angled triangle in which: QP = QR and hypotenuse PR = 7 cm
Construct a triangle using the given data: AB - AC = 1.2 cm, BC = 6.0 cm and ∠B = 60°
Construct a triangle using the given data: XY - XZ = 1.5 cm, YZ = 3.4 cm and ∠X = 45°
Construct a triangle using the given data: Perimeter of triangle is 6.4 cm, and the base angles are 60° and 45°
