Advertisements
Advertisements
Question
Construct a ΔRST with side ST = 5.4 cm, RST = 60° and the perpendicular from R on ST = 3.0 cm.
Advertisements
Solution
Steps of construction:
1. Draw a line segment ST = 5.4 cm.
2. With S as centre, draw XS making an angle of 60° with ST i.e. XST = 60°.
3. Draw a straight line PQ parallel to ST at a distance of 3 cm from ST.
4. PQ meets XS at R.
5. Join RT.
Thus, RST is the required triangle with angle RST = 60°.
APPEARS IN
RELATED QUESTIONS
In ∆ STU, l(ST) = 7 cm, l(TU) = 4 cm, l(SU) = 5 cm
Draw an equilateral triangle with side 6.5 cm.
Construct a triangle of the measures given below.
In ∆ABC, l(AC) = 7.5 cm, m ∠ABC = 90°, l(BC) = 5.5 cm.
Construct ∆ABC such that m∠A = 55°, m∠B = 60°, and l(AB) = 5.9 cm.
Construct ∆EFG from the given measures. l(FG) = 5 cm, m∠EFG = 90°, l(EG) = 7 cm.
In ∆LMN, l(LM) = 6.2 cm, m∠LMN = 60°, l(MN) = 4 cm. Construct ∆LMN.
Construct a triangle using the given data: PQ = 4.8cm, QR = 6.3cm and PR = 5.5cm
Construct a triangle using the given data: DE = 5cm, ∠D = 75° and ∠E = 60°
Construct a triangle PQR with PQ = 5.4 cm, QR = 4.6 cm and ∠Q = 60°. Draw the perpendicular PS at QR, measure the lengths of SP and SQ,
In Construction of △ABC where AB = 3 cm, BC = 5 cm, and ∠ABC = 60°, which side must be drawn first as the base?
