Advertisements
Advertisements
Question
Construct a ΔRST with side ST = 5.4 cm, RST = 60° and the perpendicular from R on ST = 3.0 cm.
Advertisements
Solution
Steps of construction:
1. Draw a line segment ST = 5.4 cm.
2. With S as centre, draw XS making an angle of 60° with ST i.e. XST = 60°.
3. Draw a straight line PQ parallel to ST at a distance of 3 cm from ST.
4. PQ meets XS at R.
5. Join RT.
Thus, RST is the required triangle with angle RST = 60°.
APPEARS IN
RELATED QUESTIONS
Construct a triangle of the measures given below.
In the right-angled ∆STU, hypotenuse SU = 5 cm and l(ST) = 4 cm.
Construct ∆ABC such that m∠A = 55°, m∠B = 60°, and l(AB) = 5.9 cm.
Construct a triangle using the given data: AB = 6.5cm, BC = 8.4cm and AC = 7.2cm
Construct a triangle using the given data: DE = 6.5cm, EF = 5.8cm and DF = 4.2cm
Construct a triangle using the given data: DE = 5cm, ∠D = 75° and ∠E = 60°
Construct an isosceles triangle in which: PQ = QR, PR = 4.5 cm and ∠R = 60°
Construct a triangle using the given data: Perimeter of triangle is 10.6 cm, and the base angles are 60° and 45°
Select the correct sequence for constructing a triangle given the three sides:
For constructing △XYZ where XY = 6 cm, YZ = 5 cm, and XZ = 4 cm, which construction method should be used?
For Construction of △ABC where AB = 4 cm, ∠A = 60°, and ∠B = 30°, what is the critical step used to locate vertex C?
