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प्रश्न
Construct a ΔRST with side ST = 5.4 cm, RST = 60° and the perpendicular from R on ST = 3.0 cm.
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उत्तर
Steps of construction:
1. Draw a line segment ST = 5.4 cm.
2. With S as centre, draw XS making an angle of 60° with ST i.e. XST = 60°.
3. Draw a straight line PQ parallel to ST at a distance of 3 cm from ST.
4. PQ meets XS at R.
5. Join RT.
Thus, RST is the required triangle with angle RST = 60°.
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संबंधित प्रश्न
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
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