Advertisements
Advertisements
प्रश्न
Construct a triangle PQR with PQ = 5.4 cm, QR = 4.6 cm and ∠Q = 60°. Draw the perpendicular PS at QR, measure the lengths of SP and SQ,
Advertisements
उत्तर
Steps:
1. Draw PQ = 5.4 cm.
2. At P, construct ∠PQT = 60°.
3. With Q as centre and radius 4.6 cm, draw an arc intersecting ray QT at R.
4. Join PR.
Thus, PQR is the required triangle.
Draw PU, the perpendicular bisector of QR intersecting QR at S.
Then, we have
SQ = 2.3 cm and SP = 4.8 cm
APPEARS IN
संबंधित प्रश्न
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Construct a triangle of the measures given below.
In ∆ABC, l(AC) = 7.5 cm, m ∠ABC = 90°, l(BC) = 5.5 cm.
Construct a triangle of the measures given below.
Construct ∆EFG from the given measures. l(FG) = 5 cm, m∠EFG = 90°, l(EG) = 7 cm.
Construct a triangle using the given data: BC = 6cm, AC = 5.0cm and ∠C = 60°
Construct a triangle using the given data: BC = 6.0cm, ∠B = 60° and ∠C = 45°
Construct a triangle using the following data: PQ + PR = 10.6 cm, QR = 4.8 cm and ∠R = 45°
Construct a triangle using the following data: DE + EF = 10.3 cm, EF = 6.4 cm and ∠E = 75°
Construct a ΔRST with side ST = 5.4 cm, RST = 60° and the perpendicular from R on ST = 3.0 cm.
In Construction of triangle ABC where AB = 3 cm, BC = 5 cm, and ∠ABC = 60°, which side must be drawn first as the base?
