Advertisements
Advertisements
प्रश्न
Construct a triangle PQR with PQ = 5.4 cm, QR = 4.6 cm and ∠Q = 60°. Draw the perpendicular PS at QR, measure the lengths of SP and SQ,
Advertisements
उत्तर
Steps:
1. Draw PQ = 5.4 cm.
2. At P, construct ∠PQT = 60°.
3. With Q as centre and radius 4.6 cm, draw an arc intersecting ray QT at R.
4. Join PR.
Thus, PQR is the required triangle.
Draw PU, the perpendicular bisector of QR intersecting QR at S.
Then, we have
SQ = 2.3 cm and SP = 4.8 cm
APPEARS IN
संबंधित प्रश्न
Draw triangle with the measures given below.
In ∆FUN, l(FU) = 5 cm, l(UN) = 4.6 cm, m∠U = 110°
Construct a triangle using the given data: PQ = 4.8cm, QR = 6.3cm and PR = 5.5cm
Construct a triangle using the given data: BC = 6cm, AC = 5.0cm and ∠C = 60°
Construct a triangle using the given data: DE = 5cm, ∠D = 75° and ∠E = 60°
Construct a triangle using the following data: PQ + PR = 10.6 cm, QR = 4.8 cm and ∠R = 45°
Construct a triangle using the following data: DE + EF = 10.3 cm, EF = 6.4 cm and ∠E = 75°
Construct a triangle using the given data: XY - XZ = 1.5 cm, YZ = 3.4 cm and ∠X = 45°
Construct a triangle using the given data: Perimeter of triangle is 9 cm, and the base angles are 60° and 45°
Construct a ΔPQR with ∠Q = 60°, ∠R = 45° and the perpendicular from P to QR be 3.5 cm. Measure PQ.
Which tool is essential for drawing arcs while constructing a triangle using given side measurements?
