Advertisements
Advertisements
Question
Draw a schematic diagram of an electric circuit consisting of a battery of two cells each of 1.5 V, 5 Ω, 10 Ω and 15 Ω resistors and a plug key, all connected in series.
Advertisements
Solution
The emf of each cell is 1.5 V.
When the two cells are connected in series, the emf of the battery becomes (1.5 + 1.5) V = 3 V.
Therefore, the schematic diagram of the series circuit is as follows:
APPEARS IN
RELATED QUESTIONS
In which direction do electrons flow?
In 10 s, charge of 25 C leaves a battery, and 200 J of energy are delivered to an outside circuit a result.
What is the p.d. across the battery?
In the circuit diagram given below five resistances of 10 Ω, 40 Ω, 30 Ω, 20 Ω, and 60 Ω are connected as shown to a 12 V battery.
Calculate:
(a) total resistance in the circuit.
(b) total current flowing in the circuit.
Consider the circuit given below:
(a) In which circuit are the lamps dimmest?
(b) In which circuit or circuits are the lamps of equal brightness to the lamps in circuit (i)?
(c) Which circuit gives out the maximum light?
Name the principle on which a transformer works.
Complete the following:
1 kWh = _________ J
Calculate the current through a 60 W lamp rated 250 V. If the line voltage falls to 200 V, how is power consumed by the bulb affected?
A geyser is rated 1500 W, 250 V. This geyser is connected to 250 V mains. Calculate:
- The current drawn,
- The energy consumed in 50 hours, and
- The cost of energy consumed at ₹ 4.20 per kWh.
What determines the direction of flow of electrons between two charged conductors kept in contact?
The number of electrons constituting a 1-coulomb charge is ______.
