Advertisements
Advertisements
प्रश्न
Draw a schematic diagram of an electric circuit consisting of a battery of two cells each of 1.5 V, 5 Ω, 10 Ω and 15 Ω resistors and a plug key, all connected in series.
Advertisements
उत्तर
The emf of each cell is 1.5 V.
When the two cells are connected in series, the emf of the battery becomes (1.5 + 1.5) V = 3 V.
Therefore, the schematic diagram of the series circuit is as follows:
APPEARS IN
संबंधित प्रश्न
A battery and three lamps are connected as shown:
Which of the following statements about the currents at X, Y and Z is correct?
(a) The current at Z is greater than that at Y.
(b) The current at Y is greater than that at Z.
(c) The current at X equals the current at Y.
(d) The current at X equals the current at Z.
Two resistors of 2.0 Ω and 3.0 Ω are connected (a) in series (b) in parallel, with a battery of 6.0 V and negligible internal resistance. For each case draw a circuit diagram and calculate the current through the battery.
What is international convention of colour coding in a cable?
Two resistors of 4 Ω and 6 Ω are connected in parallel. The combination is
connected across a 6 volt battery of negligible resistance. Calculate:
( i) The power supplied by the battery,
(ii) The power dissipated in each resistor.
A charge of 80 C flows in a conductor for 2 minutes.
(a) Calculate the current flowing through the conductor.
(b) If the current through a heater is 4 A what charge must be passing in 8 seconds?
An electric bulb is rated '100 W, 250 V'. How much current will the bulb draw if connected to a 250 V supply?
Explain, why the potential difference across the terminals of a cell is more when the cell is not in use than it is when the cell is being used.
