Advertisements
Advertisements
Question
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
10.4 cm
Advertisements
Solution
Construction:
Step 1: Drawn a line and marked two points A and B on it so that AB = 10.4 cm.
Step 2: Using compass with A as centre and radius more than half of the length of AB, drawn two arcs of same length one above AB and one below AB.
Step 3: With the same radius and B as centre drawn two arcs to cut the arcs drawn in step 2 and marked the points of intersection of the arcs as C and D.
Step 4: Joined C and D. CD intersects AB.
Marked the points of intersection as O. CD is the required perpendicular bisector.
Now ∠AOC = 90°, AO = BO = 5.2 cm
APPEARS IN
RELATED QUESTIONS
Draw a line segment PQ = 4.8 cm. Construct the perpendicular bisector of PQ.
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
58 mm
Only one perpendicular bisector can be drawn to a given line segment.
Infinitely many perpendiculars can be drawn to a given ray.
Copy figure on your notebook and draw a perpendicular from P to line m, using (i) set squares (ii) protractor (iii) ruler and compass. How many such perpendicular are you able to draw?
Bisect ∠XYZ of figure.
Draw the perpendicular bisector of `overline"XY"` whose length is 10.3 cm.
- Take any point P on the bisector drawn. Examine whether PX = PY
-
If M is the midpoint of `overline"XY"`, what can you say about the lengths MX and XY?
Which two conditions, when combined, define the Perpendicular Bisector of a line segment AB?
If point X lies on the perpendicular bisector of segment AB, then:
If a line passes through the midpoint of segment AB but does not form a 90° angle, it is:
