Advertisements
Advertisements
Question
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
10.4 cm
Advertisements
Solution

Construction:
Step 1: Drawn a line and marked two points A and B on it so that AB = 10.4 cm.
Step 2: Using compass with A as centre and radius more than half of the length of AB, drawn two arcs of same length one above AB and one below AB.
Step 3: With the same radius and B as centre drawn two arcs to cut the arcs drawn in step 2 and marked the points of intersection of the arcs as C and D.
Step 4: Joined C and D. CD intersects AB.
Marked the points of intersection as O. CD is the required perpendicular bisector.
Now ∠AOC = 90°, AO = BO = 5.2 cm
APPEARS IN
RELATED QUESTIONS
Draw a line segment PQ = 4.8 cm. Construct the perpendicular bisector of PQ.
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
8 cm
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
58 mm
Draw an angle of 60° using ruler and compasses and divide it into four equal parts. Measure each part.
Draw a line segment of length 9.5 cm and construct its perpendicular bisector.
Draw a line segment of length 12.8 cm. Using compasses, divide it into four equal parts. Verify by actual measurement.
Repeat Question 6, if `overline"AB"` happens to be a diameter.
What property defines the Uniqueness of the perpendicular bisector?
What is the minimum compass opening required when constructing a perpendicular bisector of line segment AB?
If a line passes through the midpoint of segment AB but does not form a 90° angle, it is:
