Advertisements
Advertisements
Question
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
5.6 cm
Advertisements
Solution

Construction:
Step 1: Drawn a line and marked two points A and B on it so that AB = 5.6 cm
Step 2: Using compass with A as centre and radius more than half of the length of AB, drawn two arcs of the same length, one above AB and one below AB
Step 3: With the same radius and B as centre drawn two arcs to cut the arcs drawn in step 2 and marked the points of intersection of the arcs as C and D
Step 4: Joined C and D. CD intersects AB. Marked the point of intersection as ‘O’.
CD is the required perpendicular bisector of AB.
Now ∠AOC = 90°
AO = BO
= 2.8 cm
APPEARS IN
RELATED QUESTIONS
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
7 cm
It is possible to draw two bisectors of a given angle.
Infinitely many perpendiculars can be drawn to a given ray.
Draw a line segment of length 7 cm. Draw its perpendicular bisector, using ruler and compasses.
Bisect ∠XYZ of figure.

Bisect a right angle, using ruler and compasses. Measure each part. Bisect each of these parts. What will be the measure of each of these parts?
Draw `overline"AB"` of length 7.3 cm and find its axis of symmetry.
Draw the perpendicular bisector of `overline"XY"` whose length is 10.3 cm.
- Take any point P on the bisector drawn. Examine whether PX = PY
-
If M is the midpoint of `overline"XY"`, what can you say about the lengths MX and XY?
Repeat Question 6, if `overline"AB"` happens to be a diameter.
Which two conditions, when combined, define the Perpendicular Bisector of a line segment AB?
