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प्रश्न
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
10.4 cm
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उत्तर
Construction:
Step 1: Drawn a line and marked two points A and B on it so that AB = 10.4 cm.
Step 2: Using compass with A as centre and radius more than half of the length of AB, drawn two arcs of same length one above AB and one below AB.
Step 3: With the same radius and B as centre drawn two arcs to cut the arcs drawn in step 2 and marked the points of intersection of the arcs as C and D.
Step 4: Joined C and D. CD intersects AB.
Marked the points of intersection as O. CD is the required perpendicular bisector.
Now ∠AOC = 90°, AO = BO = 5.2 cm
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संबंधित प्रश्न
In each of the following, draw perpendicular through point P to the line segment AB :
(i)
(ii)
(iii)
Draw a line segment AB = 5.5 cm. Mark a point P, such that PA = 6 cm and PB = 4.8 cm. From point P, draw a perpendicular to AB.
Draw a line segment AB of length 5.5 cm. Bisect it using a compass and ruler.
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Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of `overline"OA"` and `overline"OB"`. Let them meet at P. Is PA = PB ?
Which two conditions, when combined, define the Perpendicular Bisector of a line segment AB?
What property defines the Uniqueness of the perpendicular bisector?
