Advertisements
Advertisements
प्रश्न
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
10.4 cm
Advertisements
उत्तर

Construction:
Step 1: Drawn a line and marked two points A and B on it so that AB = 10.4 cm.
Step 2: Using compass with A as centre and radius more than half of the length of AB, drawn two arcs of same length one above AB and one below AB.
Step 3: With the same radius and B as centre drawn two arcs to cut the arcs drawn in step 2 and marked the points of intersection of the arcs as C and D.
Step 4: Joined C and D. CD intersects AB.
Marked the points of intersection as O. CD is the required perpendicular bisector.
Now ∠AOC = 90°, AO = BO = 5.2 cm
APPEARS IN
संबंधित प्रश्न
In each of the following, draw perpendicular through point P to the line segment AB :
(i)

(ii)

(iii)

Draw a line segment AB = 6.2 cm. Mark a point P in AB such that BP = 4 cm. Through point P draw perpendicular to AB.
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
8 cm
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
5.6 cm
It is possible to draw two bisectors of a given angle.
Infinitely many perpendicular bisectors can be drawn to a given ray.
Draw a line segment of length 7 cm. Draw its perpendicular bisector, using ruler and compasses.
Draw a line segment of length 6.5 cm and divide it into four equal parts, using ruler and compasses.
Draw `overline"AB"` of length 7.3 cm and find its axis of symmetry.
Draw the perpendicular bisector of `overline"XY"` whose length is 10.3 cm.
- Take any point P on the bisector drawn. Examine whether PX = PY
-
If M is the midpoint of `overline"XY"`, what can you say about the lengths MX and XY?
