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प्रश्न
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
10.4 cm
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उत्तर

Construction:
Step 1: Drawn a line and marked two points A and B on it so that AB = 10.4 cm.
Step 2: Using compass with A as centre and radius more than half of the length of AB, drawn two arcs of same length one above AB and one below AB.
Step 3: With the same radius and B as centre drawn two arcs to cut the arcs drawn in step 2 and marked the points of intersection of the arcs as C and D.
Step 4: Joined C and D. CD intersects AB.
Marked the points of intersection as O. CD is the required perpendicular bisector.
Now ∠AOC = 90°, AO = BO = 5.2 cm
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संबंधित प्रश्न
It is possible to draw two bisectors of a given angle.
Infinitely many perpendiculars can be drawn to a given ray.
In the following figure, the point C is the image of point A in line l and line segment BC intersects the line l at P.

- Is the image of P in line l the point P itself?
- Is PA = PC?
- Is PA + PB = PC + PB?
- Is P that point on line l from which the sum of the distances of points A and B is minimum?
Draw an angle of 140° with the help of a protractor and bisect it using ruler and compasses.
Bisect a right angle, using ruler and compasses. Measure each part. Bisect each of these parts. What will be the measure of each of these parts?
Draw the perpendicular bisector of `overline"XY"` whose length is 10.3 cm.
- Take any point P on the bisector drawn. Examine whether PX = PY
-
If M is the midpoint of `overline"XY"`, what can you say about the lengths MX and XY?
With `overline"PQ"` of length 6.1 cm as diameter, draw a circle.
Repeat Question 6, if `overline"AB"` happens to be a diameter.
Which two conditions, when combined, define the Perpendicular Bisector of a line segment AB?
If a line passes through the midpoint of segment AB but does not form a 90° angle, it is:
